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WAEC 2019 MATHEMATICS OBJ AND ESSAY VERIFIED ANSWER

MATHEMATICS OBJ AND ESSAY VERIFIED ANSWER

READ THIS INSTRUCTIONS:

OBJECTIVES ANSWERS


Maths-Obj
1CABDBADCBC
11BCBCBAAACD
21DCCBCCABBA
31AABDDCDDCC
41BBCDCCBCCD

 

THEORY/ESSAY ANSWERS:

(1)
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(5)
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(5a)

No of red balls = 3

No of green balls = 5

No of blue balls = x

Prob.(red ball) = no of total outcome/no of possible outcome 

  1. Pr(red) = 3/3+5+x = 1/6

3/8+x = 1/6

6(3) = 1(8+x)

18 = 8 + x

X = 18 – 8 = 10

Therefore the no of blue ball = 10

 

(5b) 

Probability of picking a green ball 

P(g) = no of green balls/no of possible outcome 

P(g) = 5/3+5+10 = 5/18

=5/18

======================

(2)
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(6)

(6ai)

F ? M1M2/d²

F = KM1M2/d²

Given F = 20N, M1= 25kg, M2 = 10kg and d = 5m

20 = k(25)(10)/5²

250k = 500

k = 500/250 = 2

Expression is 

F = 2M1M2/d²

 

(6aii) 

Making d subject 

d = ?2M1M2/F

d = ?2 ×7.5×4/30

d = ?60/30 = ?2

d = ?2m or 1.41m

 

(6b) 

Draw the diagram 

X+X+60+X+80+X+40+X+20 = 540(sum of angles in a Pentagon) 

5x + 200 = 540

5x = 540 – 200

5x = 340

X = 340/5

X = 68

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(8)

(8a) 

1/3x – 1/4(x+2)>_ 3x -1?

1/3x – 1/4(x+2)>_3x – 4/3

Multiply through by the L. C. M(12), we have 

4x – 3(x + 2)>_36x – 16

4x – 3x – 6 >_ 36x – 16

-6+16 >_36x + 3x – 4x

10 >_ 35x

35x _< 10

X = 10/35

X = 2/7

 

(8bi) 

Draw the triangle 

|AB|/66 = sin35

|AB| = 66sin35 = 66×0.5736 = 37.8576

 

Draw the right angled triangle 

|AD|/|AB| = Tan52

|AD| = 37.8576 × Tan52° = 37.8576 × 1.2799 = 48.45m

Height of tower = 48.45m


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(11)

(11a) 

ar^2=1/4——–(1)

ar^5=1/32——(2)

 

Divide equations (2) by (1)

ar^3/ar^2=1/32*4/1

r^3=1/8

r=?1/8 (use the cube root sign)

r=1/2

 

Put r=1/2 into equ (1)

ar^2=1/4

a(1/2)^2=1/4

a/4=1/4

a=1, r=1/2

 

Tn =ar^n-1 , n=7

ar^7-1=ar^6

=1(1/2)^6

T7=1/64


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(12)
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==========================

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Posted by on May 12, 2019.

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